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Distance from Ajax to Swepsonville
Route Information
The driving distance from Ajax, Virginia to Swepsonville, North Carolina is 85.8 mi (138.1 km)
The straight-line (air) distance is 66.7 mi (107.3 km)
The estimated flight time is 0 hr 8 min
The estimated travel time by road is 1 hour 38 minutes
Traveling mixed highways and local roads, substantial in a south direction. Average speeds around 50 mph.
Location Details
Origin:
No image available
Destination:
Journey Summary
Traveling from Ajax, Virginia to Swepsonville, North Carolina covers 85.8 mi (138.1 km) in a south direction. This mixed highways and local roads, substantial route typically takes 1 hour 38 minutes under normal conditions.
Drivers have 3 route options between these locations (81.9-95.1 miles / 132-153 km). The primary route shown here saves 14 minutes compared to alternatives.
The route features scenic views along the way. with average speeds around 50 mph (80 km/h).
Available Routes
How is the distance calculated?
Driving distances are based on actual road data. We use advanced routing algorithms that consider traffic, tolls, highways, and local streets. For air distances (as the crow flies), we use the Vincenty formula. It's a precise method that accounts for the Earth's shape and provides accuracy up to 0.5 mm.
When multiple route options exist, we display both the shortest and fastest paths. Travel times are estimated based on typical speeds for each road type, though actual times may vary with traffic and weather conditions. All distances are shown in both miles and kilometers for convenience.