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Distance from Cedar Rapids to Shueyville

Driving Distance
10.6 mi 17 km
Flying Distance
9.0 mi 14.6 km

Route Information

The driving distance from Cedar Rapids, Iowa to Shueyville, Iowa is 10.6 mi (17 km)

The straight-line (air) distance is 9.0 mi (14.6 km)

The estimated flight time is 0 hr 1 min

The estimated travel time by road is 13 minutes

Traveling mixed highways and local roads, short in a south direction. Average speeds around 48 mph.

Location Details

Origin:

Cedar Rapids
Place Cedar Rapids
State/Province Iowa
Country US
Latitude 41.97788
Longitude -91.665623
GPS 41.97788° N, 91.665623° W
Local Time 5:51 AM
Timezone America/Chicago

Destination:

Shueyville
Place Shueyville
State/Province Iowa
Country US
Latitude 41.847677
Longitude -91.646109
GPS 41.847677° N, 91.646109° W
Local Time 5:51 AM
Timezone America/Chicago

Journey Summary

Traveling from Cedar Rapids, Iowa to Shueyville, Iowa covers 10.6 mi (17 km) in a south direction. This mixed highways and local roads, short route typically takes 13 minutes under normal conditions.

The route features scenic views along the way. with average speeds around 48 mph (77 km/h).

How is the distance calculated?

Driving distances are based on actual road data. We use advanced routing algorithms that consider traffic, tolls, highways, and local streets. For air distances (as the crow flies), we use the Vincenty formula. It's a precise method that accounts for the Earth's shape and provides accuracy up to 0.5 mm.

When multiple route options exist, we display both the shortest and fastest paths. Travel times are estimated based on typical speeds for each road type, though actual times may vary with traffic and weather conditions. All distances are shown in both miles and kilometers for convenience.