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Distance from Cranbury to Wachapreague
Route Information
The driving distance from Cranbury, New Jersey to Wachapreague, Virginia is 257.5 mi (414.4 km)
The straight-line (air) distance is 197.6 mi (317.9 km)
The estimated flight time is 0 hr 24 min
The estimated travel time by road is 4 hours 55 minutes
Traveling highway, long-distance in a southwest direction. Average speeds around 61 mph.
Location Details
Origin:
Destination:
Journey Summary
Traveling from Cranbury, New Jersey to Wachapreague, Virginia covers 257.5 mi (414.4 km) in a southwest direction. This highway, long-distance route typically takes 4 hours 55 minutes under normal conditions.
Drivers have 3 route options between these locations (252.6-273.4 miles / 407-440 km). The primary route shown here saves 38 minutes compared to alternatives.
The route features scenic views along the way. with average speeds around 61 mph (98 km/h).
Available Routes
How is the distance calculated?
Driving distances are based on actual road data. We use advanced routing algorithms that consider traffic, tolls, highways, and local streets. For air distances (as the crow flies), we use the Vincenty formula. It's a precise method that accounts for the Earth's shape and provides accuracy up to 0.5 mm.
When multiple route options exist, we display both the shortest and fastest paths. Travel times are estimated based on typical speeds for each road type, though actual times may vary with traffic and weather conditions. All distances are shown in both miles and kilometers for convenience.