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Distance from Ewart to Searsboro

Driving Distance
13.4 mi 21.6 km
Flying Distance
6.4 mi 10.3 km

Route Information

The driving distance from Ewart, Iowa to Searsboro, Iowa is 13.4 mi (21.6 km)

The straight-line (air) distance is 6.4 mi (10.3 km)

The estimated flight time is 0 hr 1 min

The estimated travel time by road is 16 minutes

Traveling mixed highways and local roads, short in a southwest direction. Average speeds around 41 mph.

Location Details

Origin:


No image available
Place Ewart
State/Province Iowa
Country US
Latitude 41.641109
Longitude -92.610466
GPS 41.641109° N, 92.610466° W
Local Time 3:41 PM
Timezone America/Chicago

Destination:


No image available
Place Searsboro
State/Province Iowa
Country US
Latitude 41.580553
Longitude -92.703524
GPS 41.580553° N, 92.703524° W
Local Time 3:41 PM
Timezone America/Chicago

Journey Summary

Traveling from Ewart, Iowa to Searsboro, Iowa covers 13.4 mi (21.6 km) in a southwest direction. This mixed highways and local roads, short route typically takes 16 minutes under normal conditions.

Drivers have 3 route options between these locations (11.4-13.4 miles / 18-22 km).

The route features scenic views along the way. with average speeds around 41 mph (66 km/h).

Available Routes

Ewart Rd and IA-146 S
13.4 mi 16 minutes
Shortest Fastest
450th Ave and IA-146 S
11.5 mi 16 minutes
475th Ave
11.4 mi 18 minutes

How is the distance calculated?

Driving distances are based on actual road data. We use advanced routing algorithms that consider traffic, tolls, highways, and local streets. For air distances (as the crow flies), we use the Vincenty formula. It's a precise method that accounts for the Earth's shape and provides accuracy up to 0.5 mm.

When multiple route options exist, we display both the shortest and fastest paths. Travel times are estimated based on typical speeds for each road type, though actual times may vary with traffic and weather conditions. All distances are shown in both miles and kilometers for convenience.