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Distance from Gregory to Sequoyah

Driving Distance
19.7 mi 31.7 km
Flying Distance
14.0 mi 22.5 km

Route Information

The driving distance from Gregory, Oklahoma to Sequoyah, Oklahoma is 19.7 mi (31.7 km)

The straight-line (air) distance is 14.0 mi (22.5 km)

The estimated flight time is 0 hr 2 min

The estimated travel time by road is 23 minutes

Traveling mixed highways and local roads, moderate in a north direction. Average speeds around 53 mph.

Location Details

Origin:

Gregory
Place Gregory
State/Province Oklahoma
Country US
Latitude 36.170286
Longitude -95.565105
GPS 36.170286° N, 95.565105° W
Local Time 7:12 AM
Timezone America/Chicago

Destination:

Sequoyah
Place Sequoyah
State/Province Oklahoma
Country US
Latitude 36.372892
Longitude -95.562225
GPS 36.372892° N, 95.562225° W
Local Time 7:12 AM
Timezone America/Chicago

Journey Summary

Traveling from Gregory, Oklahoma to Sequoyah, Oklahoma covers 19.7 mi (31.7 km) in a north direction. This mixed highways and local roads, moderate route typically takes 23 minutes under normal conditions.

The route features scenic views along the way. with average speeds around 53 mph (85 km/h).

How is the distance calculated?

Driving distances are based on actual road data. We use advanced routing algorithms that consider traffic, tolls, highways, and local streets. For air distances (as the crow flies), we use the Vincenty formula. It's a precise method that accounts for the Earth's shape and provides accuracy up to 0.5 mm.

When multiple route options exist, we display both the shortest and fastest paths. Travel times are estimated based on typical speeds for each road type, though actual times may vary with traffic and weather conditions. All distances are shown in both miles and kilometers for convenience.