Distance from Hospers, Iowa to Ceylon, Minnesota

Hospers Ceylon
Total Distance
102 mi
(164.1 km)
Travel Time
1 hour 38 minutes

The driving distance from Hospers, Iowa to Ceylon, Minnesota is 102 mi (164.1 km)

The straight-line (air) distance is approximately 44.4 mi (71.5 km)

Estimated travel time by road is 1 hour 38 minutes

We found 2 routes between Hospers and Ceylon.

Available Routes

Shortest
IA-60 N and IA-9 E
94.7 mi
152.3 km
1 hour 40 minutes
Fastest
IA-60 N and I-90 E
102 mi
164.1 km
1 hour 38 minutes

Route Directions

Follow Hospers Dr N to IA-60 N
1.3 mi
3 min
Continue on IA-60 N. Take I-90 E to 600th Ave in Wisconsin Township. Take exit 80 from I-90 E
80.8 mi
1 hr 13 min
Take 110th St to MN-4 S in Jay Township
5.4 mi
6 min
6 mi
6 min
Follow 50th St and Co Hwy 8 to S Center St in Ceylon
8.4 mi
9 min

Route Directions

Take Hospers Dr N to IA-60 N
1.3 mi
2 min
Follow IA-60 N and IA-9 E to IA-86 N in Dickinson County
55.1 mi
53 min
Continue on IA-86 N. Take Co Hwy 4, 50th St and Co Hwy 8 to S Center St in Ceylon
38.2 mi
44 min

Journey Details

Traveling from Hospers, Iowa to Ceylon, Minnesota covers 94.7 miles (152 km) in a east direction. This highway, substantial route typically takes 1 hour 40 minutes under normal conditions.

Drivers have 2 route options between these locations (95-102 miles / 152-164 km). The primary route shown here saves no time compared to alternatives.

The route features scenic views. During night weekday travel, expect minimal traffic congestion with average speeds around 60 mph (97 km/h) .

Journey Waypoints

Hospers

Starting Point

Archer, Iowa

102 mi to destination

1 mi
Sanborn, Iowa

Traveled 26 mi from origin

1 mi
Hartley, Iowa

77 mi to destination

2 mi
May City, Iowa

Traveled 51 mi from origin

4 mi
Milford, Iowa

51 mi to destination

1 mi
Arnolds Park Public Beach, Iowa

Traveled 77 mi from origin

2 mi
Superior, Iowa

26 mi to destination

1 mi
Huntington, Iowa

Traveled 102 mi from origin

1 mi
Ceylon

Destination