Distance from Johnson Hill, New Mexico to Alexander Place, New Mexico
Johnson Hill
Alexander Place
Total Distance
77.5 mi
(124.7 km)
Travel Time
1 hour 21 minutes
The driving distance from Johnson Hill, New Mexico to Alexander Place, New Mexico is 77.5 mi (124.7 km)
The straight-line (air) distance is approximately 31.6 mi (50.9 km)
Estimated travel time by road is 1 hour 21 minutes
Route Directions
Get on I-25 N from Pueblitos Rd and NM-408 S
3 mi
6 min
Follow I-25 N and US-60 E to NM-55 N/N Summit Ave in Mountainair
62 mi
57 min
Continue on NM-55 N to your destination
12.6 mi
17 min
Journey Details
Traveling from Johnson Hill, New Mexico to Alexander Place, New Mexico covers 77.5 miles (125 km) in a northeast direction. This mixed highways and local roads, substantial route typically takes 1 hour 21 minutes under normal conditions.
Journey Waypoints
Johnson Hill
Starting Point
Alexander Place
Destination