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Distance from Johntown to Garvin

Driving Distance
48.6 mi 78.2 km
Flying Distance
38.9 mi 62.6 km

Route Information

The driving distance from Johntown, Texas to Garvin, Oklahoma is 48.6 mi (78.2 km)

The straight-line (air) distance is 38.9 mi (62.6 km)

The estimated flight time is 0 hr 5 min

The estimated travel time by road is 48 minutes

Traveling highway, moderate in a northeast direction. Average speeds around 63 mph.

Location Details

Origin:


No image available
Place Johntown
State/Province Texas
Country US
Latitude 33.422889
Longitude -95.169667
GPS 33.422889° N, 95.169667° W
Local Time 7:22 AM
Timezone America/Chicago

Destination:

Garvin
Place Garvin
State/Province Oklahoma
Country US
Latitude 33.953997
Longitude -94.942444
GPS 33.953997° N, 94.942444° W
Local Time 7:22 AM
Timezone America/Chicago

Journey Summary

Traveling from Johntown, Texas to Garvin, Oklahoma covers 48.6 mi (78.2 km) in a northeast direction. This highway, moderate route typically takes 48 minutes under normal conditions.

The route features scenic views along the way. with average speeds around 63 mph (101 km/h).

How is the distance calculated?

Driving distances are based on actual road data. We use advanced routing algorithms that consider traffic, tolls, highways, and local streets. For air distances (as the crow flies), we use the Vincenty formula. It's a precise method that accounts for the Earth's shape and provides accuracy up to 0.5 mm.

When multiple route options exist, we display both the shortest and fastest paths. Travel times are estimated based on typical speeds for each road type, though actual times may vary with traffic and weather conditions. All distances are shown in both miles and kilometers for convenience.