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Distance from Laudolff Beach to Sevastopol
Route Information
The driving distance from Laudolff Beach, Wisconsin to Sevastopol, Wisconsin is 107 mi (172.1 km)
The straight-line (air) distance is 87.9 mi (141.4 km)
The estimated flight time is 0 hr 11 min
The estimated travel time by road is 1 hour 53 minutes
Traveling highway, substantial in a northeast direction. Average speeds around 56 mph.
Location Details
Origin:
No image available
Destination:
Journey Summary
Traveling from Laudolff Beach, Wisconsin to Sevastopol, Wisconsin covers 107 mi (172.1 km) in a northeast direction. This highway, substantial route typically takes 1 hour 53 minutes under normal conditions.
Drivers have 3 route options between these locations (105.4-141.9 miles / 170-228 km). The primary route shown here saves 15 minutes compared to alternatives.
The route features scenic views along the way. with average speeds around 56 mph (90 km/h).
Available Routes
How is the distance calculated?
Driving distances are based on actual road data. We use advanced routing algorithms that consider traffic, tolls, highways, and local streets. For air distances (as the crow flies), we use the Vincenty formula. It's a precise method that accounts for the Earth's shape and provides accuracy up to 0.5 mm.
When multiple route options exist, we display both the shortest and fastest paths. Travel times are estimated based on typical speeds for each road type, though actual times may vary with traffic and weather conditions. All distances are shown in both miles and kilometers for convenience.