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Distance from Lewis to Sandy Creek Airpark

Driving Distance
70 mi 112.7 km
Flying Distance
26.2 mi 42.2 km

Route Information

The driving distance from Lewis, Florida to Sandy Creek Airpark, Florida is 70 mi (112.7 km)

The straight-line (air) distance is 26.2 mi (42.2 km)

The estimated flight time is 0 hr 3 min

The estimated travel time by road is 1 hour 19 minutes

Traveling mixed highways and local roads, substantial in a west direction. Average speeds around 50 mph.

Location Details

Origin:


No image available
Place Lewis
State/Province Florida
Country US
Latitude 30.213809
Longitude -85.059082
GPS 30.213809° N, 85.059082° W
Local Time 10:10 AM
Timezone America/New_York

Destination:


No image available
Place Sandy Creek Airpark
State/Province Florida
Country US
Latitude 30.102743
Longitude -85.478568
GPS 30.102743° N, 85.478568° W
Local Time 9:10 AM
Timezone America/Chicago

Journey Summary

Traveling from Lewis, Florida to Sandy Creek Airpark, Florida covers 70 mi (112.7 km) in a west direction. This mixed highways and local roads, substantial route typically takes 1 hour 19 minutes under normal conditions.

The route features scenic views, toll sections. with average speeds around 50 mph (80 km/h).

How is the distance calculated?

Driving distances are based on actual road data. We use advanced routing algorithms that consider traffic, tolls, highways, and local streets. For air distances (as the crow flies), we use the Vincenty formula. It's a precise method that accounts for the Earth's shape and provides accuracy up to 0.5 mm.

When multiple route options exist, we display both the shortest and fastest paths. Travel times are estimated based on typical speeds for each road type, though actual times may vary with traffic and weather conditions. All distances are shown in both miles and kilometers for convenience.