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Distance from Oswalt to Searsboro

Driving Distance
39.6 mi 63.8 km
Flying Distance
31.8 mi 51.1 km

Route Information

The driving distance from Oswalt, Iowa to Searsboro, Iowa is 39.6 mi (63.8 km)

The straight-line (air) distance is 31.8 mi (51.1 km)

The estimated flight time is 0 hr 4 min

The estimated travel time by road is 40 minutes

Traveling highway, moderate in a east direction. Average speeds around 58 mph.

Location Details

Origin:


No image available
Place Oswalt
State/Province Iowa
Country US
Latitude 41.695822
Longitude -93.297707
GPS 41.695822° N, 93.297707° W
Local Time 3:30 PM
Timezone America/Chicago

Destination:


No image available
Place Searsboro
State/Province Iowa
Country US
Latitude 41.580553
Longitude -92.703524
GPS 41.580553° N, 92.703524° W
Local Time 3:30 PM
Timezone America/Chicago

Journey Summary

Traveling from Oswalt, Iowa to Searsboro, Iowa covers 39.6 mi (63.8 km) in a east direction. This highway, moderate route typically takes 40 minutes under normal conditions.

Drivers have 2 route options between these locations (39.6-39.6 miles / 64-64 km).

The route features scenic views along the way. with average speeds around 58 mph (93 km/h).

Available Routes

I-80 E
39.6 mi 40 minutes
Shortest Fastest
I-80 E and Hwy T38 S
39.6 mi 43 minutes

How is the distance calculated?

Driving distances are based on actual road data. We use advanced routing algorithms that consider traffic, tolls, highways, and local streets. For air distances (as the crow flies), we use the Vincenty formula. It's a precise method that accounts for the Earth's shape and provides accuracy up to 0.5 mm.

When multiple route options exist, we display both the shortest and fastest paths. Travel times are estimated based on typical speeds for each road type, though actual times may vary with traffic and weather conditions. All distances are shown in both miles and kilometers for convenience.