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Distance from Ozette to Sekiu

Driving Distance
23.8 mi 38.3 km
Flying Distance
18.5 mi 29.7 km

Route Information

The driving distance from Ozette, Washington to Sekiu, Washington is 23.8 mi (38.3 km)

The straight-line (air) distance is 18.5 mi (29.7 km)

The estimated flight time is 0 hr 2 min

The estimated travel time by road is 37 minutes

Traveling mixed highways and local roads, moderate in a east direction. Average speeds around 42 mph.

Location Details

Origin:

Ozette
Place Ozette
State/Province Washington
Country US
Latitude 48.154788
Longitude -124.667177
GPS 48.154788° N, 124.667177° W
Local Time 2:55 PM
Timezone America/Los_Angeles

Destination:

Sekiu
Place Sekiu
State/Province Washington
Country US
Latitude 48.262779
Longitude -124.30108
GPS 48.262779° N, 124.30108° W
Local Time 2:55 PM
Timezone America/Los_Angeles

Journey Summary

Traveling from Ozette, Washington to Sekiu, Washington covers 23.8 mi (38.3 km) in a east direction. This mixed highways and local roads, moderate route typically takes 37 minutes under normal conditions.

The route features scenic views along the way. with average speeds around 42 mph (68 km/h).

How is the distance calculated?

Driving distances are based on actual road data. We use advanced routing algorithms that consider traffic, tolls, highways, and local streets. For air distances (as the crow flies), we use the Vincenty formula. It's a precise method that accounts for the Earth's shape and provides accuracy up to 0.5 mm.

When multiple route options exist, we display both the shortest and fastest paths. Travel times are estimated based on typical speeds for each road type, though actual times may vary with traffic and weather conditions. All distances are shown in both miles and kilometers for convenience.