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Distance from Patterson Park to Arbutus

Driving Distance
9.7 mi 15.6 km
Flying Distance
6.9 mi 11.1 km

Route Information

The driving distance from Patterson Park, Maryland to Arbutus, Maryland is 9.7 mi (15.6 km)

The straight-line (air) distance is 6.9 mi (11.1 km)

The estimated flight time is 0 hr 1 min

The estimated travel time by road is 21 minutes

Traveling secondary roads, short in a west direction. Average speeds around 28 mph.

Location Details

Origin:

Patterson Park
Place Patterson Park
State/Province Maryland
Country US
Latitude 39.289684
Longitude -76.579878
GPS 39.289684° N, 76.579878° W
Local Time 10:52 PM
Timezone America/New_York

Destination:

Arbutus
Place Arbutus
State/Province Maryland
Country US
Latitude 39.254551
Longitude -76.69997
GPS 39.254551° N, 76.69997° W
Local Time 10:52 PM
Timezone America/New_York

Journey Summary

Traveling from Patterson Park, Maryland to Arbutus, Maryland covers 9.7 mi (15.6 km) in a west direction. This secondary roads, short route typically takes 21 minutes under normal conditions.

Drivers have 3 route options between these locations (9.6-12.7 miles / 15-20 km).

The route features scenic views along the way. with average speeds around 28 mph (45 km/h).

Available Routes

E Baltimore St and I-95 S
9.7 mi 21 minutes
Shortest Fastest
I-95 S and I-695 N
12.7 mi 21 minutes
Tolls
I-95 S
9.6 mi 21 minutes

How is the distance calculated?

Driving distances are based on actual road data. We use advanced routing algorithms that consider traffic, tolls, highways, and local streets. For air distances (as the crow flies), we use the Vincenty formula. It's a precise method that accounts for the Earth's shape and provides accuracy up to 0.5 mm.

When multiple route options exist, we display both the shortest and fastest paths. Travel times are estimated based on typical speeds for each road type, though actual times may vary with traffic and weather conditions. All distances are shown in both miles and kilometers for convenience.