Distance from Sempronius, New York to Sampson, New York
The driving distance from Sempronius, New York to Sampson, New York is 58.9 mi (94.8 km)
The straight-line (air) distance is approximately 18.4 mi (29.7 km)
Estimated travel time by road is 1 hour 14 minutes
We found 3 routes between Sempronius and Sampson.
Available Routes
Route Directions
Take NY-41A N to Pine Ridge Rd in Sennett
Take Chestnut Ridge Rd to NY-5 E
Take Turnpike Rd, US-20 W, NY-414 S/Ovid St and NY-96A S to Sampson State Park in Romulus
Route Directions
Take NY-41A N, NY-38A N, US-20 W and NY-318 W to Whiskey Hill Rd in Junius
Continue on Whiskey Hill Rd to Waterloo
Take NY-96A S to Sampson State Park in Romulus
Route Directions
Take NY-41A N, NY-38A N, US-20 W and NY-414 S/Ovid St to Sampson State Park in Romulus
Journey Details
Traveling from Sempronius, New York to Sampson, New York covers 54.6 miles (88 km) in a west direction. This mixed highways and local roads, moderate route typically takes 1 hour 10 minutes under normal conditions.
Drivers have 3 route options between these locations (55-60 miles / 88-96 km). The primary route shown here saves 5 minutes compared to alternatives.
The route features scenic views. During night weekday travel, expect minimal traffic congestion with average speeds around 49 mph (79 km/h) .
Journey Waypoints
Sempronius
Starting Point
Sampson
Destination