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Distance from Denton to Seymour Heights
Route Information
The driving distance from Denton, Tennessee to Seymour Heights, Tennessee is 51.3 mi (82.6 km)
The straight-line (air) distance is 32.3 mi (52.0 km)
The estimated flight time is 0 hr 4 min
The estimated travel time by road is 55 minutes
Traveling mixed highways and local roads, moderate in a west direction. Average speeds around 46 mph.
Location Details
Origin:
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Destination:
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Journey Summary
Traveling from Denton, Tennessee to Seymour Heights, Tennessee covers 51.3 mi (82.6 km) in a west direction. This mixed highways and local roads, moderate route typically takes 55 minutes under normal conditions.
Drivers have 3 route options between these locations (43.9-59.7 miles / 71-96 km). The primary route shown here saves 6 minutes compared to alternatives.
The route features scenic views along the way. with average speeds around 46 mph (74 km/h).
Available Routes
How is the distance calculated?
Driving distances are based on actual road data. We use advanced routing algorithms that consider traffic, tolls, highways, and local streets. For air distances (as the crow flies), we use the Vincenty formula. It's a precise method that accounts for the Earth's shape and provides accuracy up to 0.5 mm.
When multiple route options exist, we display both the shortest and fastest paths. Travel times are estimated based on typical speeds for each road type, though actual times may vary with traffic and weather conditions. All distances are shown in both miles and kilometers for convenience.