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Distance from Polsgrove to Luxemburg

Driving Distance
73 mi 117.5 km
Flying Distance
61.5 mi 99.0 km

Route Information

The driving distance from Polsgrove, Illinois to Luxemburg, Iowa is 73 mi (117.5 km)

The straight-line (air) distance is 61.5 mi (99.0 km)

The estimated flight time is 0 hr 7 min

The estimated travel time by road is 1 hour 38 minutes

Traveling mixed highways and local roads, substantial in a west direction. Average speeds around 45 mph.

Location Details

Origin:


No image available
Place Polsgrove
State/Province Illinois
Country US
Latitude 42.168354
Longitude -90.023737
GPS 42.168354° N, 90.023737° W
Local Time 5:27 AM
Timezone America/Chicago

Destination:


No image available
Place Luxemburg
State/Province Iowa
Country US
Latitude 42.602772
Longitude -91.074021
GPS 42.602772° N, 91.074021° W
Local Time 5:27 AM
Timezone America/Chicago

Journey Summary

Traveling from Polsgrove, Illinois to Luxemburg, Iowa covers 73 mi (117.5 km) in a west direction. This mixed highways and local roads, substantial route typically takes 1 hour 38 minutes under normal conditions.

The route features scenic views along the way. with average speeds around 45 mph (72 km/h).

How is the distance calculated?

Driving distances are based on actual road data. We use advanced routing algorithms that consider traffic, tolls, highways, and local streets. For air distances (as the crow flies), we use the Vincenty formula. It's a precise method that accounts for the Earth's shape and provides accuracy up to 0.5 mm.

When multiple route options exist, we display both the shortest and fastest paths. Travel times are estimated based on typical speeds for each road type, though actual times may vary with traffic and weather conditions. All distances are shown in both miles and kilometers for convenience.