Distance from Pomeroy, Washington to Whipsaw Saddle, Idaho

Pomeroy Whipsaw Saddle
Total Distance
126.7 mi
(203.9 km)
Travel Time
2 hours 24 minutes

The driving distance from Pomeroy, Washington to Whipsaw Saddle, Idaho is 126.7 mi (203.9 km)

The straight-line (air) distance is approximately 47.4 mi (76.3 km)

Estimated travel time by road is 2 hours 24 minutes

This route includes Toll roads along the way.

Route Directions

Take US-12 E and US-95 S to Old Hwy 95 in Idaho County
118.8 mi
2 hr 1 min
Drive to Doumecq Rd
7.9 mi
22 min

Journey Details

Traveling from Pomeroy, Washington to Whipsaw Saddle, Idaho covers 126.7 miles (204 km) in a southeast direction. This highway, substantial route typically takes 2 hours 24 minutes under normal conditions.

The route features toll sections. During night weekend travel, expect typical weekend traffic patterns with average speeds around 56 mph (90 km/h) .

Journey Waypoints

Pomeroy

Starting Point

Pataha, Washington

109 mi to destination

4 mi
Cloverland, Washington

Traveled 27 mi from origin

4 mi
Craige, Washington

Traveled 55 mi from origin

2 mi
Zaza, Idaho

55 mi to destination

2 mi
Boles, Idaho

27 mi to destination

4 mi
Whipsaw Saddle

Destination

Destination
Address
Whipsaw Saddle · Idaho · US
Coordinates
45.792661, -116.34931
Timezone
America/Boise
Local Time
9:57 PM - Friday, May 9
Origin
Pomeroy
Pomeroy
Address
Pomeroy · Washington · US
Coordinates
46.474874, -117.60269
Timezone
America/Los_Angeles
Local Time
8:57 PM - Friday, May 9
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