Distance from Shadehill, South Dakota to Petrel, North Dakota

Shadehill Petrel
Total Distance
17.5 mi
(28.1 km)
Travel Time
20 minutes

The driving distance from Shadehill, South Dakota to Petrel, North Dakota is 17.5 mi (28.1 km)

The straight-line (air) distance is approximately 8.2 mi (13.2 km)

Estimated travel time by road is 20 minutes

We found 2 routes between Shadehill and Petrel.

Available Routes

Shortest Fastest
SD-73 N
17.1 mi
27.5 km
19 minutes
SD-73 N and US-12 W
17.5 mi
28.1 km
20 minutes

Route Directions

17.5 mi
20 min

Route Directions

17.1 mi
19 min

Journey Details

Traveling from Shadehill, South Dakota to Petrel, North Dakota covers 17.1 miles (27 km) in a northwest direction. This mixed highways and local roads, moderate route typically takes 19 minutes under normal conditions.

Drivers have 2 route options between these locations (17-17 miles / 27-28 km). The primary route shown here saves 16 seconds compared to alternatives.

The route features scenic views. During evening weekend travel, expect typical weekend traffic patterns with average speeds around 54 mph (87 km/h) .

Journey Waypoints

Shadehill

Starting Point

Summerville, South Dakota

19 mi to destination

1 mi
Lemmon, South Dakota

9 mi to destination

4 mi
Petrel

Destination