Distance from Zephyrhills, Florida to Lakeland Highlands, Florida
The driving distance from Zephyrhills, Florida to Lakeland Highlands, Florida is 31.9 mi (51.4 km)
The straight-line (air) distance is approximately 14.7 mi (23.6 km)
Estimated travel time by road is 47 minutes
We found 3 routes between Zephyrhills and Lakeland Highlands.
Available Routes
Route Directions
Take FL-39 S, I-4 E, County Line Rd and Ewell Rd to Scott Lake Rd in Lakeland Highlands
Route Directions
Take 8th St to Gall Blvd
Take FL-39 S, I-4 E and FL-570 E to School House Rd in Medulla
Follow Fitzgerald Rd to Scott Lake Rd in Lakeland Highlands
Route Directions
Take 7th St and 6th Ave to Gall Blvd
Take FL-39 S to FL-39A N in Hillsborough County
Get on I-4 E in Plant City
Continue on I-4 E. Take FL-570 E to E Highland Dr in Lakeland
Take Cleveland Heights Blvd to Scott Lake Rd in Lakeland Highlands
Journey Details
Traveling from Zephyrhills, Florida to Lakeland Highlands, Florida covers 29.7 miles (48 km) in a southeast direction. This mixed highways and local roads, moderate route typically takes 40 minutes under normal conditions.
Drivers have 3 route options between these locations (30-32 miles / 48-51 km). The primary route shown here saves 8 minutes compared to alternatives.
The route features scenic views, toll sections. During midday weekday travel, expect lighter midday traffic with average speeds around 44 mph (71 km/h) .
Journey Waypoints
Zephyrhills
Starting Point
Lakeland Highlands
Destination
