Distance from Boynton Beach, Florida to Sand Cut, Florida
The driving distance from Boynton Beach, Florida to Sand Cut, Florida is 59.7 mi (96.1 km)
The straight-line (air) distance is approximately 25.9 mi (41.6 km)
Estimated travel time by road is 1 hour 21 minutes
This route includes Toll roads along the way.
We found 3 routes between Boynton Beach and Sand Cut.
Available Routes
Route Directions
Get on Florida's Tpke from FL-804 W/Boynton Beach Blvd
Follow Florida's Tpke and FL-80 W/US-98
Continue to Pahokee
Follow E Main St and US-441 N/US-98 W
Drive to Hole in the Wall Rd
Route Directions
Get on I-95 N
Drive along FL-80 W/US-98
Continue to Pahokee
Follow E Main St and US-441 N/US-98 W
Drive to Hole in the Wall Rd
Route Directions
Get on Florida's Tpke from Old Boynton Road and FL-804 W
Follow Florida's Tpke and FL-80 W/US-98
Continue to Pahokee
Follow E Main St and US-441 N/US-98 W
Drive to Hole in the Wall Rd
Journey Details
Traveling from Boynton Beach, Florida to Sand Cut, Florida covers 59.7 miles (96 km) in a northwest direction. This mixed highways and local roads, moderate route typically takes 1 hour 21 minutes under normal conditions.
Drivers have 3 route options between these locations (60-61 miles / 96-97 km). The primary route shown here saves 15 seconds compared to alternatives.
The route features scenic views, toll sections, coastal roads. During midday weekend travel, expect typical weekend traffic patterns with average speeds around 42 mph (68 km/h) .
Journey Waypoints
Boynton Beach
Starting Point
Sand Cut
Destination
