Distance from Seneca, Kansas to Auburn, Nebraska

Seneca Auburn
Total Distance
51.5 mi
(82.8 km)
Travel Time
54 minutes

The driving distance from Seneca, Kansas to Auburn, Nebraska is 51.5 mi (82.8 km)

The straight-line (air) distance is approximately 25.2 mi (40.6 km)

Estimated travel time by road is 54 minutes

We found 3 routes between Seneca and Auburn.

Available Routes

Shortest
KS-63 N and US-75 N
49.9 mi
80.4 km
54 minutes
Fastest
US-75 N
51.5 mi
82.8 km
54 minutes
US-36 E and US-75 N
55 mi
88.5 km
56 minutes

Route Directions

0.5 mi
1 min
Follow KS-63 N, NE-8 E and US-75 N to E St in Auburn
50.8 mi
52 min
0.1 mi
0 min

Route Directions

55 mi
56 min

Route Directions

0.5 mi
1 min
Take KS-63 N, NE-105 N and US-75 N to E St in Auburn
49.3 mi
52 min
0.1 mi
0 min

Journey Details

Traveling from Seneca, Kansas to Auburn, Nebraska covers 49.9 miles (80 km) in a north direction. This mixed highways and local roads, moderate route typically takes 54 minutes under normal conditions.

Drivers have 3 route options between these locations (50-55 miles / 80-89 km). The primary route shown here saves 2 minutes compared to alternatives.

Journey Waypoints

Seneca

Starting Point

St Benedict, Kansas

58 mi to destination

2 mi
Bern, Kansas

Traveled 15 mi from origin

1 mi
Du Bois, Nebraska

44 mi to destination

2 mi
Nim City, Nebraska

Traveled 29 mi from origin

4 mi
Humboldt, Nebraska

29 mi to destination

1 mi
Howe, Nebraska

15 mi to destination

3 mi
Auburn

Destination